# A copper disc at $\;0^{0}C\;$ has a diameter of 50 cm and a hole is cut in the center with a diameter 5 cm . The diameter of the hole at $\;100^{0}C\;$ will be $\;(\alpha = 0.00016/^{0}C)\;$
$(a)\;5.08\;cm\qquad(b)\;50.8\;cm\qquad(c)\;0.508\;cm\qquad(d)\;100.08\;cm$