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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Coordinate Geometry

Intercept on the line $y=x$ by the circle $x^2+y^2-2x=0$ is $AB$ equation of the circle on AB as a diameter is :

$\begin{array}{1 1}(A)\;x^2+y^2+x-y-=0 \\(B)\;x^2+y^2-x+y=0 \\(C)\;x^2+y^2+x+y=0 \\(D)\;x^2+y^2-x-y=0 \end{array}$

1 Answer

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=> $x=0 \;or \;x=1$
=> $y=0 \;or\;y=1$
$\therefore$ extremities of diameter of the required circle are $(0,0)$ and $(1,1)$ Hence the equation of the circle is
Hence D is the correct answer.
answered Apr 9, 2014 by meena.p

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