Ask Questions, Get Answers

Want to ask us a question? Click here
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
0 votes

Starting from the same initial conditions , an ideal gas expands from volume $\;V_{1}\;$ to $\;V_{2}\;$ in three different ways . The work done by the gas is $\;W_{1}\;$ if the process is purely isothermal , $\;W_{2}\;$ if purely isobaric and $\;W_{3}\;$ if purely adiabatic . Then :

$(a)\;W_{2} >W_{1} >W_{3}\qquad(b)\;W_{2} >W_{3} >W_{1}\qquad(c)\;W_{1} >W_{2} >W_{3}\qquad(d)\;W_{1} >W_{3} >W_{2}$

Can you answer this question?

1 Answer

0 votes
Answer : $\;W_{2} >W_{1} >W_{3}$
Explanation :
Curve 1 - isobaric process
Curve 2 - isothermal process
Curve 3 - idiabatic process
Since work done Area under PV graph
$= W_{2} >W_{1} >W_{3}$
answered Apr 9, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App