Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
0 votes

Find the equation of the chord of the parabola $y^2=12x$ which is bisected at $(5,-7)$

$\begin{array}{1 1}(A)\;6x-7y+19=0\\(B)\;6x+7y+19=0 \\(C)\;6x+9y+20=0 \\(D)\;3x+4y+12=0 \end{array}$

Can you answer this question?

1 Answer

0 votes
Here, $x_1=5;\qquad y_1=-7 ;\qquad a=3$
Equation of the chord is $S_1=T$
=> $6x+7y+19=0$
Hence B is the correct answer.
answered Apr 9, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App