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Coordinate Geometry
Find the equation of the chord of the parabola $y^2=12x$ which is bisected at $(5,-7)$
$\begin{array}{1 1}(A)\;6x-7y+19=0\\(B)\;6x+7y+19=0 \\(C)\;6x+9y+20=0 \\(D)\;3x+4y+12=0 \end{array}$
jeemain
math
class11
coordinate-geometry-conic -sections
circle
ch11
medium
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asked
Apr 9, 2014
by
meena.p
retagged
Sep 26, 2014
by
sharmaaparna1
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Here, $x_1=5;\qquad y_1=-7 ;\qquad a=3$
Equation of the chord is $S_1=T$
$(-7)^2-12(5)=y(-7)-6(x+5)$
=> $6x+7y+19=0$
Hence B is the correct answer.
answered
Apr 9, 2014
by
meena.p
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