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Given $x=2+5i$, the value of $x^3-5x^2+33x-19$ is

$\begin{array}{1 1}(A)10 \\ (B) 0 \\ (C) -19 \\(D) none\;of\;these \end{array}$

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$\Rightarrow x^2-4x+29=0$
Dividing $x^3-5x^2+33x-19$ by $x^2-4x+29$ we get,
Putting $x=2+5i$
$\Rightarrow 10$
Hence (A) is the correct answer.
answered Apr 9, 2014 by sreemathi.v

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