Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If $\mid z\mid=1$ and $z\neq \pm 1$ then $\large\frac{z}{1-z^2}$ lie on

$\begin{array}{1 1}(A)x- axis \\ (B) y-axis \\ (C) \text{A line passing through origin} \\(D) |z|=2 \end{array}$

Can you answer this question?

1 Answer

0 votes
$\Rightarrow \omega=\large\frac{1}{-2iIm(z)}$
$\Rightarrow \omega$ is purely imaginary
$\Rightarrow \omega$ lies on $y$-axis
Hence (B) is the correct answer.
answered Apr 9, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App