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Find the equation of the circle which touches the both axes in first quadrant and whose radius is $a$?

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  • The equation of a circle with radius $r$ having centre $(h, k) $ is given by $(x – h)^2 + (y – k)^2 = r^2$
Given that the circle touches both the $x$ and $y$ axes in the first quadrant and the radius is $a$.
For a circle of radius $a$, the centre is $(a,a)$.
Therefore, the equation of the circle becomes $(x – a)^2 + (y – a)^2 = a^2$
answered Apr 9, 2014 by balaji.thirumalai

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