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Conic Sections
Find the equation of the circle which touches the both axes in first quadrant and whose radius is $a$?
cbse
class11
math
conic-sections
circle
exemplar
sec-a
easy
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asked
Apr 9, 2014
by
balaji.thirumalai
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1 Answer
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The equation of a circle with radius $r$ having centre $(h, k) $ is given by $(x – h)^2 + (y – k)^2 = r^2$
Given that the circle touches both the $x$ and $y$ axes in the first quadrant and the radius is $a$.
For a circle of radius $a$, the centre is $(a,a)$.
Therefore, the equation of the circle becomes $(x – a)^2 + (y – a)^2 = a^2$
answered
Apr 9, 2014
by
balaji.thirumalai
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