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In the chlorination of isobutane, which product will be formed in excess

$\begin {array} {1 1} (A)\;(CH_3)_2 CHCH_2Cl & \quad (B)\;(CH_3)_3CCl \\ (C)\;\text{Both of above} & \quad (D)\;\text{None of above} \end {array}$

1 Answer

Chlorination of most higher alkanes gives a mixture of isomeric monochloro products as well as more highly halogentated compounds.
Chlorine is relatively unselective.
It does not discriminate greatly among the different type of hydrogen atoms ( primary, secondary and territary ) in an alkane .
An example is the light- promoted chlorination of isobutane .
answered Apr 9, 2014 by thanvigandhi_1
edited Sep 21 by meena.p
 
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