Comment
Share
Q)

In $CH_3 − CH_2 − CH_2 − Br$, $C-Br$ bond is formed by the overlapping of

$\begin {array} {1 1} (A)\;sp^3-2pz & \quad (B)\;2sp^3-3pz \\ (C)\;2sp^3-2pz & \quad (D)\;2sp^3-4pz \end {array}$

$Br$ lies in $4^th$ period , so Bromine has $4pz$ orbital thus $4pz$ orbital overlap with $sp^3$ hybrid orbital of $C$ adjescent to it.