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Questions  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Expand the expression: $\large(\frac{x}{3} + \frac{1}{x})$$^5$

$\begin{array}{1 1} \large\frac{x^5}{243} + \large\frac{5x^3}{81} + \large\frac{10x}{27} +\large\frac{10}{9x}+\large\frac{5}{3x^3}+\large\frac{1}{x^5} \\ \large\frac{243}{x^5} + \large\frac{81}{5x^3} + \large\frac{27}{10x} +\large\frac{9x}{10}+\large\frac{3x^3}{5}+\large\frac{x^5}{1} \\ \large\frac{81}{x^5} + \large\frac{27}{5x^3} + \large\frac{9}{10x} +\large\frac{x}{10}+\large\frac{9x^3}{5}+\large\frac{x^5}{3} \\ \large\frac{x^5}{81} + \large\frac{5x^3}{27} + \large\frac{10x}{9} +\large\frac{10}{3x}+\large\frac{5}{x^3}+\large\frac{1}{x^5} \end{array} $

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