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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
+1 vote

The equation of the directrise of the parabola $y^2+4y+4x+2=0$ is

$\begin{array}{1 1}(A)\;x=-1 \\(B)\;x=1 \\(C)\;x=-\frac{3}{2} \\(D)\;x=\frac{3}{2} \end{array}$

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1 Answer

0 votes
Given equation of parabola
$y^2+4y+4x+2=0$
or $(y+2)^2+4x+2=0$
or $(y+2)^2=-4(x -\large\frac{1}{2})$
Its directise is $x-\large\frac{1}{2}$$=1$
or $x=\large\frac{3}{2}$
Hence D is the correct answer.
answered Apr 10, 2014 by meena.p
edited Sep 27, 2014 by sharmaaparna1
 

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