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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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Find the shortest distance between the lines $\large \frac{x-8}{3} = \frac{y+9}{-16}=\frac{z-10}{7}$ and $\large\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5} $ Also, find equation of the line of shortest distance.

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