$\begin{array}{1 1}(A)\;3x+2y+14=0 \\(B)\;3x+2y-25=0 \\(C)\;2x-3y+10=0 \\(D)\;none\;of\;these \end{array}$

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Equation of the axis of symmetry

$y-1=\large\frac{3-1}{2+1}$

=> $2x-3y+5=0$

Let co-ordinate of the point of interested of direction and axis of symmetric be $(x_1,y_1)$ then

$\large\frac{x_1+2}{2}$$=2^{-1}$

=> $ x_1=-4$

$\large\frac{y_1+3}{2} $$=1$

$y_1=-1$

equation of the directrix is

$3(x+4)+2(y+1)=0$

=> $3x+2y+14=0$

Hence A is the correct answer.

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