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Q)

Find the asymptotes of the hyperbola. $xy=4x+3y$

$\begin{array}{1 1}(A)\;x-3=0\;y+4=0 \\(B)\;x-3=0\;y-4=0 \\(C)\;x+3=0\;y+4=0\\(D)\;x+3=0\;y-4=0 \end{array}$

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A)
Given $xy=4x+3y$
=> $ x(y-4)=3(y-4) +12$
=> $(x-4)(y-4)=12$
$\therefore $ joint equation of asymptotes is $(x-3)(y-4)=0$
Hence $x-3=0,y-4=0$
Hence B is the correct answer.
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