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Two wires A and B have the same length and area of cross - section. But Young's modulus of A is two times the Young's modulus of B. Then the ratio of the force constant of A to that of B is

$\begin{array}{1 1}(A)\;1 \\(B)\;2 \\(C)\;\large\frac{1}{2} \\ (D)\; \sqrt 2 \end{array}$

1 Answer

The ratio of the force constant of A to that of B is 2
Hence B is the correct answer.
answered Apr 11, 2014 by

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1 answer

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1 answer