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Q)

$\large\frac{2ab}{25c^2}\times \frac{5bc}{4a^2}$=

$\begin{array}{1 1}(A)\;\large\frac{b}{10a}&(B)\;\large\frac{b}{5ac}\\(C)\;\large\frac{b^2}{7ac}&(D)\;\large\frac{b^2}{10ac}\end{array} $

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