Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS
0 votes

Two particles A and B of equal masses are suspended from two mass less springs of spring constants $k_1$ and $k_2$ respectively. If the maximum velocities , during oscillations ,are equal , the ratio amplitudes of A and B is

$\begin{array}{1 1}(A)\;\sqrt {\frac{k_1}{k_2}} \\(B)\;\frac{k_2}{k_1} \\(C)\;\sqrt {\large\frac{k_2}{k_1}} \\ (D)\; \frac{k_1}{k_2} \end{array} $

Can you answer this question?

1 Answer

0 votes
The ratio amplitudes of A and B is $\sqrt {\large\frac{k_2}{k_1}}$
Hence C is the correct answer.
answered Apr 11, 2014 by meena.p
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App