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The escape velocity for a body projected vertically upwards from the surface of earth is $11\;km/s$. If the body is projected at an angle of $45^{\circ}$ with the vertical , the escape velocity will be

$\begin{array}{1 1}(A)\;11 \sqrt 2 km/s \\(B)\;22\;km/s \\(C)\;11\;km/s \\ (D)\;\frac{11}{\sqrt 2} \end{array} $

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1 Answer

The escape velocity will be $11\;km/s$
Hence C is the correct answer.
answered Apr 11, 2014 by meena.p
 

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