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What is the equilibrium expression for the reaction $P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)} ? $

$\begin{array}{1 1}(A)\;Kc= [P_4O_{10}]/P_4][O_2]^5 \\(B)\;Kc= 1/[0_2]^5 \\(C)\;Kc=[O_2]^5\\ (D)\; Kc=[P_4O_{10}]/5[P_4][O_2] \end{array} $

1 Answer

$P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)} $ is reaction $Kc= 1/[0_2]^5 $
Hence B is the correct answer.
answered Apr 11, 2014 by meena.p
 

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