Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS
0 votes

What is the equilibrium expression for the reaction $P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)} ? $

$\begin{array}{1 1}(A)\;Kc= [P_4O_{10}]/P_4][O_2]^5 \\(B)\;Kc= 1/[0_2]^5 \\(C)\;Kc=[O_2]^5\\ (D)\; Kc=[P_4O_{10}]/5[P_4][O_2] \end{array} $
Can you answer this question?

1 Answer

0 votes
$P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)} $ is reaction $Kc= 1/[0_2]^5 $
Hence B is the correct answer.
answered Apr 11, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App