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# What is the equilibrium expression for the reaction $P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)} ?$

$\begin{array}{1 1}(A)\;Kc= [P_4O_{10}]/P_4][O_2]^5 \\(B)\;Kc= 1/[0_2]^5 \\(C)\;Kc=[O_2]^5\\ (D)\; Kc=[P_4O_{10}]/5[P_4][O_2] \end{array}$
Can you answer this question?

$P_{4(5)}+50_{(2(g)} \rightleftharpoons P_4O_{10(5)}$ is reaction $Kc= 1/[0_2]^5$
Hence B is the correct answer.
answered Apr 11, 2014 by