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Number of sigma and pi bonds present in $CH_2 = C= CHCH$ is

$\begin{array}{1 1}(A)\;9,2 \\(B)\;7,2 \\(C)\;9,3 \\ (D)\;7,4 \end{array} $
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Number of sigma and pi bonds present in $CH_2 = C= CHCH$ is $9,2$
Hence A is the correct answer.
answered Apr 11, 2014 by meena.p
 
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