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# Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadractic equation.

$\begin{array}{1 1}(A)\;x^2+18x+16=0 \\(B)\;x^2-18x-16=0 \\(C)\;x^2+18x-16=0 \\ (D)\;x^2-18x+16=0 \end{array}$

## 1 Answer

$x^2-18x+16=0$
Hence D is the correct answer.
answered Apr 11, 2014 by

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