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Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadractic equation.
$\begin{array}{1 1}(A)\;x^2+18x+16=0 \\(B)\;x^2-18x-16=0 \\(C)\;x^2+18x-16=0 \\ (D)\;x^2-18x+16=0 \end{array} $
aims
class-xii
q21
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asked
Apr 11, 2014
by
meena.p
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1 Answer
$x^2-18x+16=0 $
Hence D is the correct answer.
answered
Apr 11, 2014
by
meena.p
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