Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
AIMS
Next similar question
Answer
Comment
Share
Q)
The foci of the ellipse $\large\frac{x^2}{16}+\frac{y^2}{b^2}$$=1$ and the hyperbola $\large\frac{x^2}{144}-\frac{y^2}{81} =\frac{1}{25}$ coincide. Then the value of $b^2$ is
$\begin{array}{1 1}(A)\;1 \\(B)\;5 \\(C)\;7 \\ (D)\;9 \end{array} $
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1 Answer
Found
1
answer. Click to login & view.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...