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The radius of the circle $x^2+y^2+8x+10y-8=0$ is

$\begin{array}{1 1}(A)\;49 \\(B)\;\frac{7}{2} \\(C)\;7 \\ (D)\;9 \end{array}$

The radius of the circle $x^2+y^2+8x+10y-8=0$ is $7$
Hence C is the correct answer.