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The radius of the circle $x^2+y^2+8x+10y-8=0$ is

$\begin{array}{1 1}(A)\;49 \\(B)\;\frac{7}{2} \\(C)\;7 \\ (D)\;9 \end{array} $

1 Answer

The radius of the circle $x^2+y^2+8x+10y-8=0$ is $7$
Hence C is the correct answer.
answered Apr 11, 2014 by meena.p
 
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