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# If $y=f(x)=\large\frac{2x-1}{x-2}$ then $f(y)=$

$\begin{array}{1 1}(A)\;1 \\(B)\;y \\(C)\;2y-1 \\ (D)\;y-2 \end{array}$

If $y=f(x)=\large\frac{2x-1}{x-2}$ then $f(y)=1$
Hence A is the correct answer.
answered Apr 11, 2014 by