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If $(x-1),(x+1)$ and $(x-2)$ are factors of $x^4+(p-3)x^3-(3p-5)x^2+(2p-9)x+6$ then the value of p is
$\begin{array}{1 1}(A)\;1 \\(B)\;2 \\(C)\;3 \\ (D)\;4 \end{array} $
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