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If $\;-8y-(y-5)=-13\;$ then $\;y=$

$(a)\;5\qquad(b)\;2\qquad(c)\;\large\frac{13}{9}\qquad(d)\;\large\frac{8}{9}$

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Answer : 2
Explanation :
$-8y-(y-5)=-13\;$
$-8y-y+5=-13$
$-9y=-13-5$
$y=\large\frac{18}{9}$
$y=2$
answered Apr 12, 2014 by yamini.v
 

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