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Factors of $\;(x^{2} + \large\frac{x}{6}- \large\frac{1}{6})\;$ are

$(a)\;\large\frac{1}{6} (2x+1)(3x+1)\qquad(b)\;\large\frac{1}{6} (2x+1)(3x-1)\qquad(c)\;\large\frac{1}{6} (2x-1)(3x-1)\qquad(d)\;\large\frac{1}{6} (2x-1)(3x+1)$

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Answer : $\;\large\frac{1}{6} (2x+1)(3x-1)$
Factors of $\;(x^{2} + \large\frac{x}{6}- \large\frac{1}{6})\;$ are $\;\large\frac{1}{6} (2x+1)(3x-1)$
answered Apr 13, 2014 by yamini.v
 

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