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CBSE XII
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Model Papers
Find the area bounded by the curve $x^2 = 4y$ and the straight line 4y - 2 = x
cbse
class12
modelpaper
2005
sec-a
q18
math
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asked
Jan 28, 2013
by
fingeazy
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The area of the region bounded by the curve $x^2=4y$ and the straight line $x=4y-2$ is \begin{array}{1 1}(A)\;\frac{3}{8}sq.units & (B)\;\frac{5}{8}sq.units\\(C)\;\frac{7}{8}sq.units & (D)\;\frac{9}{8} sq.units \end{array}
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The area (in square units) bonded by the curves $y^2=4x$ and $x^2=4y$ in the plane is :
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A straight line $y=mx$ passes through the intersection of the straight lines $x+2y-1=0$ and $2x-y+3=0.$Find the value of m.
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Prove that the curve \( y^2=4x\) and \( x^2=4y\) divide the area of the square bounded by \( x=0,x=4,y=4\: and \: y=0\) into three equation.
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Find the area of the region bounded by the curve $y^2=4x,x^2=4y$.
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