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Number of atoms present in 40 gram of $\;(_{1}H^{1})_{2}\;$ gas is

$(a)\;6.023\times10^{23}\qquad(b)\;1.2046\times10^{25}\qquad(c)\;2.4092\times10^{25}\qquad(d)\;20$

1 Answer

Answer : $\;2.4092\times10^{25}$
Number of atoms present in 40 gram of $\;(_{1}H^{1})_{2}\;$ gas is $\;2.4092\times10^{25}$
answered Apr 13, 2014 by yamini.v
 

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