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Roots of equation $(b-c)x^2+(c-a)x+(a-b)=0$ are

$\begin{array}{1 1}(A)\;\large\frac{c-a}{b-c},\normalsize 1&(B)\;\large\frac{a-b}{b-c},\normalsize 1\\(C)\;\large\frac{b-c}{a-b},\normalsize 1&(D)\;\large\frac{c-a}{a-b},\normalsize 1\end{array} $

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Clearly $1$ is a root of given equation .
Product of roots =$\large\frac{a-b}{b-c}$
$\Rightarrow $Another root is $\large\frac{a-b}{b-c}$
Hence (B) is the correct answer.
answered Apr 14, 2014 by sreemathi.v
 

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