logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The equation whose roots A.M=9 and G.M=4 is

$\begin{array}{1 1}(A)\;x^2+18x+16=0&(B)\;x^2+18x-16=0\\(C)\;x^2-18x+16=0&(D)\;x^2-18x-16=0\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Let the roots be $\alpha,\beta$
$\large\frac{\alpha+\beta}{2}$=A.M=$9\Rightarrow \alpha+\beta=18$
G.M=$\sqrt{\alpha\beta}=4\Rightarrow \alpha\beta=16$
$\Rightarrow $ Equation :$x^2-18x+16=0$
Hence (C) is the correct answer.
answered Apr 14, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...