$x^2-5x+3=0$
$\alpha+\beta=5$
$\alpha\beta=3$
$\large\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{19}{3}$
$\big(\large\frac{\alpha}{\beta}\big)\big(\large\frac{\beta}{\alpha}\big)$$=1$
Equation :$x^2-\large\frac{19}{3}$$x+1=0$
$\Rightarrow 3x^2-19x+3=0$
Hence (C) is the correct answer.