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# The set of values of 'a' for which roots of equation $3x^2+2x+(a-1)a=0$ are of opposite sign

$\begin{array}{1 1}(A)\;(0,1)&(B)\;(-\infty,0)\\(C)\;(0,\infty)&(D)\;(1,\infty)\end{array}$

Roots are of opposite sign
$\therefore$ Product of roots < 0
$\Rightarrow \large\frac{(a-1)a}{3}$$< 0$
$\Rightarrow a\in (0,1)$
Hence (A) is the correct answer.