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$a,b,c$ are natural no and equations $x^2-5x+a=0,x^2-6x+b=0,x^2-8x+c=0$ have exactly one root in common and common root is also a natural no.$(a+b+c)$ is minimum when common root is :

$\begin{array}{1 1}(A)\;1&(B)\;2\\(C)\;3&(D)\;4\end{array} $

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$a,b,c$ are natural no and equations $x^2-5x+a=0,x^2-6x+b=0,x^2-8x+c=0$ have exactly one root in common and common root is also a natural no.$(a+b+c)$ is minimum when common root is 1
Hence (A) is the correct answer.
answered Apr 15, 2014 by sreemathi.v
 

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