# Given,$a(p+q)^2+2bpq+c=0$ and $a(p+r)^2+2bpr+c=0$.Then the value of qr is

$\begin{array}{1 1}(A)\;p^2+\large\frac{c}{a}&(B)\;p^2+\large\frac{a}{c}\\(C)\;p^2+\large\frac{b}{a}&(D)\;p^2+\large\frac{a}{b}\end{array}$

Roots of equation $a(p+x)^2+2bpx+c=0$ are q and r
$\Rightarrow a(p^2+x^2+2px)+2bpx+c=0$
Product of roots =$qr=\large\frac{c+ap^2}{a}$$=p^2+\large\frac{c}{a}$
Hence (A) is the correct answer.