Browse Questions
Home  >>  AIMS

# If $\sin A:\cos A=4:7$,then the value of $\large\frac{7\sin A-3\cos A}{7\sin A+2\cos A}$ is

$\begin{array}{1 1}(A)\;\large\frac{3}{14}&(B)\;\large\frac{3}{2}\\(C)\;\large\frac{1}{3}&(D)\;\large\frac{1}{6}\end{array}$

$\large\frac{7\sin A-3\cos A}{7\sin A+2\cos A}$ is $\large\frac{1}{6}$
Hence (D) is the correct answer.