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# The number of atoms present in 1.6g of methane is

$\begin{array}{1 1}(A)\;6.02\times 10^{23}&(B)\;3.01\times 10^{24}\\(C)\;3.01\times 10^{23}&(D)\;6.02\times 10^{24}\end{array}$

Can you answer this question?

The number of atoms present in 1.6g of methane is $3.01\times 10^{23}$
Hence (C) is the correct answer.
answered Apr 15, 2014