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A piece of resistance wire has resistance of $4\Omega$.Its diameter is doubled.Now its resistance will be

$\begin{array}{1 1}(A)\;8\Omega&(B)\;2\Omega\\(C)\;4\Omega&(D)\;1\Omega\end{array} $

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A piece of resistance wire has resistance of $4\Omega$.Its diameter is doubled.Now its resistance will be $1\Omega$
Hence (D) is the correct answer.
answered Apr 15, 2014 by sreemathi.v
 

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