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The ratio of the radii of the nuclei $_{13}Al^{27}$ and $_{52}Te^{125}$ is approximately

$\begin{array}{1 1}(A)\;3 : 5&(B)\;27 : 125\\(C)\;13 : 52&(D)\;14 : 73\end{array}$

The ratio of the radii of the nuclei $_{13}Al^{27}$ and $_{52}Te^{125}$ is approximately 3 : 5
Hence (A) is the correct answer.