$\begin{array}{1 1}(A)\;2\; radian&(B)\;\large\frac{2}{15}\normalsize radian\\(C)\;\large\frac{2}{17}\normalsize radian&(D)\;\large\frac{3}{10}\normalsize radian\end{array} $

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- $\theta=\large\frac{l}{r}$
- $\theta$=angle subtended by arc
- $l$=length of the arc
- $r$=radius of the circle

Given :

Length =10cm

Radius=75cm

$\theta=?$

We know that $\theta=\large\frac{l}{r}$

$\Rightarrow \large\frac{10}{75}$ radians

$\Rightarrow \large\frac{2}{15}$ radians

Hence (B) is the correct answer.

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