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Express the following in the form $\;a+ib : i^{-35}$

$(a)\; i\qquad(b)\;0\qquad(c)\;- i\qquad(d)\;1$

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1 Answer

Answer : $\;i$
Explanation :
$ i^{-35} = \large\frac{1}{i^{35}} = \large\frac{1}{(i^{2})^{17} i}$
$= \large\frac{1}{-i} \times \large\frac{i}{i}$
$= \large\frac{i}{-i^{2}} = i$
answered Apr 16, 2014 by yamini.v
 

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