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Solve $\;x^{2}+2 =0 \;$

$(a)\;1\qquad(b)\;\pm \sqrt{2} i\qquad(c)\;2i\qquad(d)\;4 i$

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Answer : $\;\pm \sqrt{2} i$
Explanation :
we , have $\;x^{2}+2 =0 \;$
$x^{2} = -2$
i.e $\; x = \pm \sqrt{-2} = \pm \sqrt{2} i$
answered Apr 16, 2014 by yamini.v
 
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