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Find the distance between the points $(2,3,5)$ and $(4,3,1)$

$\begin{array}{1 1}3 \sqrt 5\\ 6 \sqrt 3 \\ 2 \sqrt 5 \\ 2 \sqrt{14}\end{array} $

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  • Distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Given two points are $A(2,3,5)$ and $B(4,3,1)$.
We know that the distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Here $x_1=2,\:y_1=3,\:z_1=5$ and
$\therefore$ The distance between the give two points $AB$ is
$\sqrt {(4-2)^2+(3-3)^2+(1-5)^2}=\sqrt {4+0+16}=\sqrt {20}=2\sqrt 5$
answered Apr 16, 2014 by rvidyagovindarajan_1

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