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Find the distance between the points $(-3,7,2)$ and $(2,4,-1)$

$\begin{array}{1 1}\sqrt{43} \\ \sqrt{19} \\ \sqrt {123} \\ \sqrt {147}\end{array} $

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  • Distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Given two points are $A(-3,7,2)$ and $B(2,4,-1)$.
We know that the distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Here $x_1=-3,\:y_1=7,\:z_1=2$ and
$x_2=2,\:y_2=4,\:z_2=-1.$
$\therefore$ The distance between the give two points $AB$ is
$\sqrt {(2+3)^2+(4-7)^2+(-1-2)^2}=\sqrt {25+9+9}=\sqrt {43}$
answered Apr 16, 2014 by rvidyagovindarajan_1
edited Apr 16, 2014 by rvidyagovindarajan_1
 

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