$\begin{array}{1 1}2 \sqrt{5} \\ 6 \\ 2 \\ 2 \sqrt{14}\end{array} $

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- Distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Given two points are $A(2,-1,3)$ and $B(-2,1,3)$.

We know that the distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here $x_1=22,\:y_1=-1,\:z_1=3$ and

$x_2=-2,\:y_2=1,\:z_2=3.$

$\therefore$ The distance between the give two points $AB$ is

$\sqrt {(-2-2)^2+(1+1)^2+3-3)^2}=\sqrt {16+4+0}=\sqrt {20}=2\sqrt {5}$

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