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Find the distance between the points $(-1,3,-4)$ and $(1,-3,-4)$

$\begin{array}{1 1}2 \sqrt{10} \\ 2 \sqrt {26} \\ 0 \\ 4 \sqrt{5} \end{array} $

1 Answer

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  • Distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Given two points are $A(-1,3,-4)$ and $B(1,-3,4)$.
We know that the distance between two points $(x_1,y_1,z_1)\:\;and \:\:(x_2,y_2,z_2)$ is given by $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Here $x_1=-1,\:y_1=3,\:z_1=-4$ and
$x_2=1,\:y_2=-3,\:z_2=4.$
$\therefore$ The distance between the give two points $AB$ is
$\sqrt {(1+1)^2+(-3-3)^2+(4+4)^2}=\sqrt {4+36+64}=\sqrt {104}=2\sqrt {26}$
answered Apr 16, 2014 by rvidyagovindarajan_1
edited Apr 16, 2014 by rvidyagovindarajan_1
 

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