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Home  >>  CBSE XI  >>  Math  >>  Trigonometric Functions
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Find the value of the trigonometric functions $cosec (-1410^{\large\circ})$

$\begin{array}{1 1}(A)\;\large\frac{1}{2}&(B)\;2\\(C)\;\large\frac{-1}{2}&(D)\;-2\end{array} $

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We know that values of $cosec x$ repeats after an interval of $2\pi$ or $360^{\large\circ}$
$\therefore cosec (-1410^{\large\circ})=cosec (-1410+4\times 360^{\large\circ})$
$\Rightarrow cosec(-1410+1440)$
$\Rightarrow cosec(30^{\large\circ})=2$
Hence (B) is the correct answer.
answered Apr 17, 2014 by sreemathi.v

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