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Home  >>  CBSE XII  >>  Math  >>  Application of Derivatives
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$f(x)=\Large\frac{x^2-1}{x^2+1} $ for every real number then minimum value of \begin{array}{1 1}(a)\;does\; not\; exist & \qquad(b)\;is\;not\;attained\;even\;though\;f\;is\;bounded\\(c)\;is\;equal\;to\;1 & \qquad(d)\;is\;equal\;to\;-1\end{array}

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