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Home  >>  CBSE XI  >>  Math  >>  Trigonometric Functions

Prove : $\sin^26x-\sin^24x=\sin 2x.\sin 10x$

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  • $\sin^2A-\sin^2B=\sin (A+B).\sin (A-B)$
L.H.S
$\sin^26x-\sin^24x=\sin(6x+4x).\sin (6x-4x)$
$\Rightarrow \sin 10x.\sin 2x$=R.H.S
Hence proved.
answered Apr 17, 2014 by sreemathi.v
 
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